Question

7. Find the modulus and argument of 1+i/1-i
​

Answer 1

Answer:

1  

Step-by-step explanation:

The modulus of a complex number z = a + bi is |z| = $\sqrt{a^2+b^2}$  

$\frac{1+i}{1-i}$ = $\frac{(1+i)(1+i)}{(1-i)(1+i)}$ = $\frac{1 + 2i - 1}{1 - (i)^2}$ = i ⇒ z = 0 + 1i

|z| = $\sqrt{0^2 + 1^2 }$ = 1