7. Find the perimeter of a rhombus, the length of whose diagonals are 16 cm 30 cm
Answers
Answered by
1
Answer:
Perimeter=68 cm
Explanation:
Side^2= (Diagonal/2)^2+(Diagonal/2)^2
On substituting the values, we get
side=17
Perimeter=4*Side
Thus, Perimeter=68 cm
Answered by
2
Answer:
Given: Diagonals AC=30cm and DB=16cm.
Since the diagonals of the rhombus bisect at right angle to each other.
Therefore, OD=
2
DB
=
2
16
=8cm
and OC=
2
AC
=
2
30
=15cm
Now, In right angle triangle DOC,
(DC)
2
=(OD)
2
+(CO)
2
⇒(DC)
2
=(8)
2
+(15)
2
⇒(DC)
2
=64+225=289
⇒DC=
289
=17cm
Perimeter of the rhombus=4× side
=4×17=68cm
Thus, the perimeter of rhombus is 68 cm
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