Question

7. Find the point on the x-axis which is equidistant from (2,-5) and (-2,9).correct answer is the brainliast ​

Answer 1

Answer:Given points A(2,−5) and B(−2,9)

Let the points be P(x,0).

So, AP=PB and AP  

2

=PB  

2

 

⇒(x−2)  

2

+(0+5)  

2

=(x+2)  

2

+(0−9)  

2

 

⇒x  

2

+4−4x+25=x  

2

+4+4x+81

⇒x  

2

+29−4x=x  

2

+85+4x

⇒−4x−4x=85−29

⇒−8x=56

⇒x=−7

Hence, point on the x-axis which is equidistant from (2,−5) and (−2,9) is (−7,0).

Step-by-step explanation: