Question

7. Find the point on the x-axis which is equidistant from (2,-5) and (-2, 9).​

Answer 1

Answer:

Hence, point on the x-axis which is equidistant from (2,−5) and (−2,9) is (−7,0)

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Answer 2

Answer ✍️

According to the question we have A(2,−5) and B(−2,9) Let the points be P(x,0). So,

AP=PB and AP2=PB2 ⇒(x−2)2+(0+5)2 = (x+2)2+(0−9)2 ⇒x2+4−4x+25=x2+4+4x+81 ⇒x2+29−4x=x2+85+4x ⇒−4x−4x=85−29 ⇒−8x=56 ⇒x=−7

• Hence, point on the x-axis which is equidistant from (2,−5) and (−2,9) is (−7,0).

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