Question

7.
Find the position of the points (-1,2). 2.-3) with respect to the line 2x - 3y + 1 =0.​

Answer 1

The point (-1,2) lies above and the point (2,-3) lies below the line 2x - 3y + 1 = 0

Step-by-step explanation:

The given equation of the straight line is 2x - 3y + 1 = 0 .......... (1)

Now, we are given two points (-1,2) and (2,-3) and we have to judge their position with respect to (1).

Now, putting x = -1 in equation (1) we get,

- 3y = - 1 - 2x = - 1 - 2(- 1) = 1

⇒ $y = - \frac{1}{3} < 2$

Therefore, the point (-1,2) lies above the straight line (1).

Again, putting x = 2 in the equation (1), we get

- 3y = - 1 - 2x = - 1 - 2(2) = - 5

⇒ $y = \frac{5}{3} > - 3$

Therefore, the point (2,-3) lies below the straight line (1).

Answer 2

Answer

B

Step-by-step explanation:

Given options are

a) Same side of the line

b) Opposite side to the line

c)Neither a nor b

d)Data in sufficient

Hence, the answer is option B

The given equation of the straight line