Question

7. Find the quotient and remainder when (7-15x-13X+5x) is divisible by (4-3x+X2)
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Answer 1

Answer:

$7 - 15x - 13x + 5x = - 23x + 7 \\ 4 - 3x + 2x = 4 - x \\ 4 - x = 0 \\ x = 4 \\ - 23x + 7 (put x = 4) \\ - 23( 4) + 7 \\-92 + 7 \\ -85\\ so \: remainder = -85$

Now,

we know that,

Q×d+R=D

Q×[4-x]+(-85)=-23x+7

Q×[4-x]=-23x+7+85

Q=(-23x+92)/4-x

Q=23

Hence,

quotient=23 and Remainder=

-85