Question

7.Find the smallest Four digit number which is divisible by 20, 25 and 30​

Answer 1

Answer:

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Step-by-step explanation:

smallest 4-digit number divisible by 20, 25 and 30 = 1,500

Answer 2

Given:

20 , 25 , 30

To find:

Find the smallest four digit number which is divisible by 20, 25 and 30​.

Solution:

• To find the smallest four digit number which is divisible by 20, 25 and 30 we need to find LCM.
• Then divide the LCM by the smallest 4 digit number(1000).
• Subtract the remainder with the LCM(300) and add with the smallest four digit number(1000)

The L C M of 20, 25 and 30 is

20 = 2²×5

25 = 5²

30 = 5×2×3

     =2²×5²×3

     = 4×25×3

LCM =300

Now $\frac{1000}{300}$ =quotient 3 and remainder is 100

Now  1000 + (300 - 100)

    1000+200 = 1200.

So the required smallest Four digit number which is divisible by 20, 25 and 30​ is 1200.