Question

7. Find the smallest number by which 320 must be divided to get a perfect cube.
10​

Answer 1

Answer:

100

Step-by-step explanation:

on taking the lcm of 320

the answer is =2*2*2*2*2*5

Therefore, the smallest no. will be

2*2*5*5=100 (ans.)

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Answer 2

Answer:

320

• Frist we will do prime factorisation

320 = 2×2×2×2×2×2×5

• now we will divide 320 by 5 as we got the two pairs of 2 but the 5 is single ,

= 320 ÷ 5

= 64

as we all know that 64 is a perfect cube .

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