Question

7. Find the smallest number which when divided by 35, 56 and 105 leaves a remainder of 6 in each case.

ans= 846
full detail ​

Answer 1

Step-by-step explanation:

we basically have to add 6 to LCM of 35 56 105

LCM=840

840+6=846

Answer 2

Answer:

846

Step-by-step explanation:

let the number be x.

A/q: dividend = divisor*quotient +remainder

1. x=35a+6

2.x=56b+6

3.x=105c+6

As you can see above equations will give as

35a=56b=105c

so you need a number which should be divided by all or you need to find LCM of all three and then add 6 to it finally

Lcm is 840

just add 6 . answer is 846