Question

7. Find the speed and average speed of a train which leaves Varanasi at 5 p.m. and
reaches Calcutta the next day at 11 a.m. The distance between the two stations is
990 km and the total time for stoppage is 3 hours between these stations.
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Answer 1

Answer:

66kmph

Step-by-step explanation:

5 pm-11 am=18 hrs

18 hrs .minus stoppage =15

Now we know that speed is equal to distance by time

so- 990/15 =66

hope it helps

Answer 2

Answer:

Speed=distance /time

Speed=990/5

Speed=158km/hr

Average speed=total distance travelled /total time taken

Average speed =990/3

Average speed =330