Question

7. Find the sum of even numbers between 100 and 200​

Answer 1

Answer:

+198+200 =(100+200)+(102+198)+(104+196)+… +(148+152)+150 If we take a gander at the reordered aggregate, we can see that there are 25 sets of even numbers in addition to an additional 150. Each combine aggregates to 300, so the aggregate is =25x300+150 =7500+150 =7650.

Answer 2

Answer:

step 1 Address the formula, input parameters & values.

Input parameters & values:

The number series 100, 101, 102, 103, . . . . , 199, 200.

The first term a = 100

The common difference d = 1

Total Number of terms n = 101

step 2 apply the input parameter values in the formula

Sum = n/2 x (a + Tn)

= (101/2) x (100 + 200)

= (101 x 300 ) / 2

100 + 101 + 102 + 103 + . . . . + 199 + 200 = 15150