7. find the sum to n terms of the A.P....,whose k term is 5k+1
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Step-by-step explanation:
give that
kth term =5k+1
ak =5k+1
putting k = 1
a1=5×1+1
= 6
similarly,
putting k =2
a2 = 5×2 +1
=11
putting k =3
=16
thus our A.P becomes 6, 11, 16....
here
first term a=6
d=11-6 = 5
we need to find the sum of n term i.e Sn
sn = n/2 (2a+(n-1) d)
putting values a =6 d = 5
=n/2 (12+ (n-1)5)
=n/2 (5N+7)
hence the sum of n term of the A.P is n/2 (5n+7)
hope it helpss !! :D
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