Math, asked by srihandattanvn, 12 days ago

7. Find the unknown value
in the given figure below

thank you ..​

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Answers

Answered by ChikukiAshi
2

Answer:

 \huge{ \blue{❆}}{ \frak{ \color{blue}{Question}}}{ \blue{❅}}

Find the unknown value in the given figure.

\huge{ \pink{✿}}{ \frak{ \color{red}{Answer}}}{ \pink{❀}}

 \large{ \frak{ \underline{To  \: find :}}}

Value of

 \sf{ \angle{x}} &  \sf{ \angle{y}}

  \large{ \frak{ \underline{Given :}}}

AB = AC

 \sf{ \angle{CBD = 130°}}

  \large{ \frak{ \underline{Solⁿ:}}}

It is given that , AB = AC

  \sf{∴ { \angle{ABC}} = { \angle{ACB}}}

Because angles opposite to equal sides are equal.

Now,

 \sf{ \angle{ABC}}  +  { \angle{CBD}} = 180{ \degree}

(Linear Pair)

 \sf{ \angle{ABC}} + 130° = 180°

 \sf{ \angle{ ABC}} = { \angle{ACB}} = 50{ \degree}

 \sf∴ { \angle{x}} = 50{ \degree}

Now, by using exterior angle property of triangle

 \sf{ \angle{x}} + { \angle{y}} = 130{ \degree}

 \sf50{ \degree} + { \angle{y}} = 130{ \degree}

 \sf∴ { \angle{y}} = 80{ \degree}

Hence,  \sf{ \angle{x}} = 50° and  \sf{ \angle{y}} = 80°

 \frak{ \green{ ☘hope \: it \: helps...}}

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Answered by Anonymous
1

Answer:

\sf{ \angle{x}} = 50° and \sf{ \angle{y}} = 80°

\frak{ \red{hope \:  this \:  is \:  helpful...}}

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