Question

7) Find the value of compound interest If , A = 5695.31 and P = 4000​

Answer 1

Answer:

Principal = (P) = ₹4,000

Principal = (P) = ₹4,000Time (t) = 2 years

Principal = (P) = ₹4,000Time (t) = 2 yearsRate (R1) = 10% and rate (R2) = 15%

Principal = (P) = ₹4,000Time (t) = 2 yearsRate (R1) = 10% and rate (R2) = 15%Amount = P (1 + (R1/100)) (1 + (R2/100))

Principal = (P) = ₹4,000Time (t) = 2 yearsRate (R1) = 10% and rate (R2) = 15%Amount = P (1 + (R1/100)) (1 + (R2/100))= ₹ 4,000 (1 + (10/100)) (1 + (15/100))

Principal = (P) = ₹4,000Time (t) = 2 yearsRate (R1) = 10% and rate (R2) = 15%Amount = P (1 + (R1/100)) (1 + (R2/100))= ₹ 4,000 (1 + (10/100)) (1 + (15/100))= ₹ 4,000 × 11/10 × 23/20 = ₹5060

Principal = (P) = ₹4,000Time (t) = 2 yearsRate (R1) = 10% and rate (R2) = 15%Amount = P (1 + (R1/100)) (1 + (R2/100))= ₹ 4,000 (1 + (10/100)) (1 + (15/100))= ₹ 4,000 × 11/10 × 23/20 = ₹5060C.I. = Amount – Principal

Principal = (P) = ₹4,000Time (t) = 2 yearsRate (R1) = 10% and rate (R2) = 15%Amount = P (1 + (R1/100)) (1 + (R2/100))= ₹ 4,000 (1 + (10/100)) (1 + (15/100))= ₹ 4,000 × 11/10 × 23/20 = ₹5060C.I. = Amount – Principal= ₹5060 - ₹4000 = ₹1060

Answer 2

Answer:

amount principal=5060-4000-1060

Step-by-step explanation:

right answet