7. Find the value of k if the points A (2,3 ) , B ( 4, k ) and C ( 6,-3 ) are collinear.
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Given points are A(2,3), B(4,k) and C(6,-3).
Here we have x1 = 2, x2 = 4, y 1 = 3, y2 = k, x3 = 6, y3 = -3.
Given that the three points are collinear.
= > x1(y2 - y3) + x2(y3 - y1) + x3(y1 - y2) = 0
= > 2(k + 3) + 4(-3 - 3) + 6(3 - k) = 0
= > 2k + 6 + 4(-6) + 18 - 6k = 0
= > 2k + 6 - 24 + 18 - 6k = 0
= > -4k + 0 = 0
= > -4k = 0
= > k = 0.
Therefore the value of k = 0.
Hope this helps!
Here we have x1 = 2, x2 = 4, y 1 = 3, y2 = k, x3 = 6, y3 = -3.
Given that the three points are collinear.
= > x1(y2 - y3) + x2(y3 - y1) + x3(y1 - y2) = 0
= > 2(k + 3) + 4(-3 - 3) + 6(3 - k) = 0
= > 2k + 6 + 4(-6) + 18 - 6k = 0
= > 2k + 6 - 24 + 18 - 6k = 0
= > -4k + 0 = 0
= > -4k = 0
= > k = 0.
Therefore the value of k = 0.
Hope this helps!
siddhartharao77:
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