7.Find the values of y for which the distance between the
points P (2, -3) and Q (10, y) is 10 units.
Answers
Answered by
1
Answer:
3 or -9
Step-by-step explanation:
pq=root of {[x2-x1]^2+[y2-y1]^2}
10=root of {[10-2]^2+[y-(-3)]^2}
10=root of {[8]^2+[y+3]^2}
10=root of {64+y^2+9+6y}
10=root of {73+y^2+6y}
[10]^2 = 73+y^2+6y
100=73+y^2+6y
0=73+y^2+6y-100
0=y^2+6y-27
0=y^2+9y-3y-27
0=y[y+9]-3[y+9]
0=[y+9][y-3]
y=-9 or y-3
Similar questions