Question

7.Find the values of y for which the distance between the
points P (2, -3) and Q (10, y) is 10 units.​

Answer 1

Answer:

3 or -9

Step-by-step explanation:

pq=root of {[x2-x1]^2+[y2-y1]^2}

10=root of {[10-2]^2+[y-(-3)]^2}

10=root of {[8]^2+[y+3]^2}

10=root of {64+y^2+9+6y}

10=root of {73+y^2+6y}

[10]^2 = 73+y^2+6y

100=73+y^2+6y

0=73+y^2+6y-100

0=y^2+6y-27

0=y^2+9y-3y-27

0=y[y+9]-3[y+9]

0=[y+9][y-3]

y=-9 or y-3