Question

7. Find the zeroes of polynomial
p(x) = 6x2 + 7x + 2 and verify the relationship
between the zeroes and the coefficients.​

Answer 1

Answer:

6x^2+7x+2

6x^2+4x+3x+2

2x(3x+2)+1(3x+2)

(3x+2)(2x+1)

x= -2/3

x= -1/2

sum of zeroes= -b/a

-2/3-1/2= -7/6

-7/6= -7/6

product of zero=c/a

-2/3×-1/2=2/6

1/3=13

Answer 2

Explanation:

6x2+7x+2=0

6x2+3x+4x+2=0

3x(2x+1) 2(2x+1)=0

(2x+1) (3x +2)=0

2x +1=0&3x +2=0

x=-1/2& x=-2/3=0

value of a=6,b=7,c=2

relation of zeroes and coefficient is

alpha +bita= 1/2+2/3= -6/7. ...... (1)

-b/a) now coefficient -(6)/7. .....(2)

from 1&2 (-b/a=alpha +bita)

product of zeroes =

(-1/2) (-2/3)=2/6

from coefficient

c/a=2/6

hope you understand and this will help you