Question

7. Find the zeros of the p(x) = (x-3)(x+2).​

Answer 1

p(x)=(x+2)(x+3) This is a quadratic polynomial . It has two zeroes .

Let P(x)=0

⇒(x+2)(x+3)=0

⇒x+2=0,x+3=0

⇒x=−2,x=−3

∴ The zeroes of the polynomial are

−2 and −3.

Answer 2

Answer:

For finding zeroes of an expression,

make it equal to zero.

=> p(x) = 0

=> (x-3)(x+2) = 0

Now, the result of product of two numbers is 0, when:

(1) either of number is 0

(2) both numbers are 0

=> (x-3) = 0 or (x+2)=0

=> x = 3 or x = -2

Thus, zeroes are 3 and -2, on putting them in the given expression of p(x), we get the result as 0.

I hope you understood the answer!