Question

7. Find three consecutive integers such that the sum of the first, twice the second, and three times the third is
- 76.​

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Let us consider $3$ consecutive numbers be: $x, x+1, x+2$

Now, given: The sum of the first, twice the second, and three times the third is $-76.$

That is:

$x+2(x+1)+3(x+2)=-76$

$x+2x+2+3x+6=-76$

$6x+8=-76$

$6x=-76-8$

$6x=-84$

$x=\frac{-84}{6}$

$x=-14.$

Therefore: the three consecutive numbers are: $-14, -14+1, -14+2$

$= -14,-13, -12$.