Question

7) Find three consecutive natural numbers such that the sum of the first and the
second is 15 more than the third.​

Answer 1

Answer:

The three consecutive numbers are 16, 17, 18.

Explanation:

Three consecutive numbers are such that the sum of first and second number is 15 more than the third number.

Find the number.

Suppose the number is $x$

Then, the consecutive numbers are :

$x, \: (x + 1), \: {\sf{and}} \: (x + 2)$

Given,

Sum of $x$ and $(x + 1)$ is 15 more than $(x + 2)$

Or,

$\implies x + (x + 1) - 15 = (x + 2)$

Solving for $\boldsymbol x$ :

$\implies x + (x + 1 )- 15 = (x + 2)$

$\implies x + x + 1 - 15 = x + 2$

$\implies 2x - 14 = x + 2$

$\implies 2x - x= 14 + 2$

${\therefore{ \boldsymbol{x = 16}}}$

${\underline{ \sf The \: first \: number \: is \bf \: 16}}$

Therefore, the other two numbers are :

• Second number $\to (x + 1)$ = 17.
• Third number $\to (x + 2)$ = 18.

_______________________

Check point :

Given that, (16 + 17) is 15 more than 18.

Or,

→ (16 + 17) - 15 = 18

→ 33 - 15 = 18

→ 18 = 18.

Hence, proved

Answer 2

Question:

Find three consecutive natural numbers such that the sum of the first and the second is 15 more than the third.

$\huge{\underline{\mathtt{\red {A}\pink{N}\green{S}\blue{W}\purple {E}\orange{R}}}}$

Three consecutive numbers = 16, 17, 18.

Solution:

Let the number be = x

Then, consecutive numbers are:-

$= x, (x + 1), (x + 2)$

Given:-

sum of x and (x+1) is 15 more than (x+2).

so, the equation will be:

$= x + (x + 1) - 15 = (x + 2)$

● Finding x.

$➪ \: x + (x + 1) - 15 = (x + 2)$

$➪ \: x + x + 1 - 15 = x + 2$

$➪ \: 2x - 14 = x + 2$

$➪ \: 2x - x = 14 + 2$

$➪ \: x = 16$

The first number is 16.

so, other two numbers are:-

$x = 16$

Second number =( x+1) = 17

Third Number =( x+2) = 18

☆Verification ☆

As we are given wíth= (16 + 17) is 15 more than 18.

Therefore

$➪ \: (16 + 17) - 15 = 18$

$➪ \: 33 - 15 = 18$

$➪ \: 18 = 18$

$\sf\red{hope\:it\:helps\:you}$