Question

7. Find three consecutive odd integers such that the sum of the first number, two less than the second
number and three more than the third number is 70.
please answer the question
in breif explanation
give ans fast please​

Answer 1

Answer:

If the first number is n the second number is 2 more than n and the third number is 4 more than n. And, here is how you mathematically represent that

n + 2(n + 2) + 3(n + 4) = 70

n + 2n + 4 +3n + 12 = 70

6n + 16 = 70

6n = 54

n = 9

=> The numbers are 9, 11, 13

Answer 2

Answer:

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