Question

7. Find zeroes of the quadratic polynomial
$x {}^{2} + 6x + 9$

Standard:- 10

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Answer 1

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$\blue {\bold {Here \: is \:the \: answer}}$

Given :
$x {}^{2} + 6x + 9$

By breaking the mid term....

We have to find two numbers such that their sum = 6 and product = 9.

By looking at the$\blue{Prime \: factorisation}$ of 9, we get two numbers as 3 and 3.

So,
⏩ x^2 + 6x + 9 = 0
⏩ x^2 + 3x + 3x + 9 = 0
⏩ x (x + 3) + 3 ( x + 3) = 0
⏩ (x + 3)(x + 3) = 0

By comparing with zero...
x + 3 = 0 and x+3 = 0
x = -3 and x = -3.

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