Question

(7.) For the reaction A + 3B2C + D. initial mole of A is twice that of B. If at equilibrium moles of B and C
are equal, then percent of B reacted is
(1) 10%
(2) 20%
(4) 60%​

Answer 1

Answer:

A+3B⇌2C+D

                                 A                     B                          C                     D

Initial conc                a                     a/2                         0                    0

At equilibrium          a-x               (a/2) - 3x                   2x                   x

(a/2)-3x = 2x

        a/2 = 5x

          x = a/10

Amount of B reacted =3x = 3a/10

Initial amt of B  = a/2

∴ percentage of B reacted = a/23a/10∗100=60