Math, asked by jaychhodvadiya853, 1 year ago

7. For what value of a, -3 is a zero of the
polynomial p (x) = x3 + 12x2 + ax + 60 ?​

Answers

Answered by singhp038
1

Answer:

19

Step-by-step explanation:

p(-3)=(-3)3+24-3x+60. 0=-27+24-3x+60. 0=-3-3x+60. 3x=57. x=19

Answered by Player71
1

Answer:

a=65

Step-by-step explanation:

p(x)=x³+12x²+ax+60

zero of -3 is 3

p(3)=0

p(3)= (3)³+12(3)²+a(x)+60 = 0

       = 27+108+3a+60 = 0

        = 3a+195 = 0

         = a = \frac{195}{3}

         = a = 65

the value of a is 65

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