Question

7. For what value of k, the product of the zeros of x² – 3kx + 2k² – 1 is 7?
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Answer 1

Answer:

Irrational

Product of the roots =

1

2k

2

−1

⇒2k

2

−1=7 or k=±2

∴ Equation is x

2

±6x+7=0

D=

36−4×7

=2

2

∴ Roots are irrational.