7. Four persons A, B, C and D are to speak at a function along with four
others. If they all speak in random order, find the probability that A speaks
before B, B speaks before C and C speaks before D.
(a) 1/4(b) 1/6 (d) 1)25
c)1)24
Answers
Answered by
1
Answer:
i think its answer is 1/4
Step-by-step explanation:
because there and four people and saying in random
Similar questions