Geography, asked by gg5338796, 9 hours ago

7. From the following distribution of hourly wage (in rupees) of firmemployees, find the modal hourly wage.Less Less Less Less Less Less Less LessHourlythan than than than thanthan than thanwage10 20 30 40 50 60 70 80No. of2 15 6095 122 140 150employees82


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Answers

Answered by py5794294
0

Answer:

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Answered by ChitranjanMahajan
0

Correct Question

From the following distribution of firm employees' hourly wage (in rupees), find the modal hourly wage.

\begin{tabular}{|c|} {\underline{Hourly Wage less than (in Rs.)}}\\10 \\20 \\30 \\ 40 \\ 50 \\ 60 \\ 70 \\ 80  \\\end{tabular}\begin{tabular}{|c|} {\underline{No. of Employees}}\\2 \\15\\ 60 \\95\\ 122 \\140\\ 150\\182  \\\end{tabular}

Answer

The hourly wage is Rs. 27.62 (Approx)

Given

Frequency distribution

To Find

Modal hourly wage

Solution

Here we first need to convert this into a class-frequency distribution.

Since this is a less-than-frequency distribution,

  • The less-than values are the upper limits of the class.
  • The lower limits will be less than the value of the previous class.
  • We will subtract the cumulative frequency given with that of the previous row to arrive at our frequency of that class.

Hence we get

\begin{tabular}{|c|} {\underline{Hourly Wage (in Rs.)}}\\0-10 \\10-20 \\20-30 \\ 30-40 \\ 40-50 \\ 50-60 \\ 60-70 \\ 70-80 \\ \\\end{tabular}\begin{tabular}{|c|} {\underline{No. of Employees}}\\2 \\13\\ 45 \\35\\ 27 \\18\\ 10\\32\\ \overline{\sum f = 182}  \\\end{tabular}

To Calculate Mode we will

  • First, find the highest frequency
  • Then we will take note of the lower limit of that class.
  • Then we will take note of the frequencies before and after it.
  • Lastly, we will take note of the class size.

Mode = l + (f₁ - f₀)/(2f₁ - f₀ - f₂) X h

where,

l = lower limit of the modal class

f₁ = frequency of modal class

f₀ = frequency of class before the modal class

f₂ = frequency of the class after the modal class.

h = class size = upper limit - lower limit

Here, the highest frequency is 45 hence,

l = 20

f₁ = 45

f₀ = 13

f₂ = 35

h = 10

Hence, mode

= 20 + (45 - 13)/(90 - 13 - 35)  X 10

= 20 + 32/42 X10

= 20 + 7.619

= Rs. 27.619

= Rs. 27.62 (Approx)

Therefore, the hourly wage is Rs. 27.62 (Approx)

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