7 g of a metal (M) on reaction with oxygen forms 9 g of metal oxide having formula MO. The atomic mass of metal M (in g/mol) is
•0 24
•40
•065
•56
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Answer:
Atomic mass = 56 u
Explanation:
Mass of metal = 7 g
Mass of metal oxide = 9 g
Mass of oxygen = 9-7
= 2 g
Equivalent mass of metal = (Mass of metal x 8)/Mass of oxygen
= (7 x 8)/2
= 28
But we know , Equivalent mass = Atomic mass / valency
28 = At. mass / 2
At. mass = 28 x 2 = 56 u
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