Question

7. Graphically determine the area of the triangle formed by x - y = 2 , x + y = 6 and y = 0

Class 10

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Answer 1

Hey!


• Given 1st equation is x - y = 2

So, x = 2 + y ........ ( i )

Now , putting value of y we get value of x , we can put any integral value for y !!


↪ If y = 0

x = 2 + y

x = 2

( x , y ) = ( 2 , 0 )

↪ If y = 1

x = 2 - 1

x = 1

( x , y ) = ( 3 , 1 )

↪ If y = -1

x = 1

( x , y ) = ( 1 , -1 )


• Given 2nd equation is x + y = 6

So, x = 6 - y

Doing by the same method as above we get ;

( x , y ) = ( 2 , 4 )

( x , y ) = ( 3 , 3 )

( x , y ) = ( 4 , 2 )


• Given 3rd equation is y = 0

✏ If any value just suppose as a as y = a then we plot a on the y - axis and draw a parallel line to x - axis

Here , we have y = 0
So, we plot y = 0 and draw a line parallel to x - axis !!

[ This line ( parallel line ) can be coincide also ]


[ Refer the pic for the diagram ]



area of ∆ABC =
$= \frac{1}{2} \times base \: \times height$


$= \frac{1}{2} \times 4 \times 2 \\ = 4 \: {unit}^{2}$


Area of ∆ABC is equal to 4unit² !!