Question

7. How many 176 ohm resistors (parallel) are required to carry current 5 Ampere on 220 volt

line ​

Answer 1

Answer:

Explanation:

let us assume there is n number of resistor required. since all the resistors are connected in parallel connection so the equivalence resistance = R = 176/n Ω

Using ohms law

V =IR

220 = 5×(176/n)

n = (176×5)/220

n = 880/220 = 4

So the number of resistor would be 4

Answer 2

Given :-

• Potential difference (V) = 220 V

• Current (I) = 5 A

To find :-

• How many 176 ohm resistors in parallel are required to carry 5 ampere on a 220 volts ?

Solution :-

we know that,

$\orange{\bigstar}\:{\underline{\boxed{\bf\pink{R=\dfrac{V}{I}}}}}$

$\rm\longrightarrow\:R=\cancel\dfrac{220}{5}$

$\rm\longrightarrow\:R=44\:\Omega$

Hence the total resistance of circuit is 44 Ω.

Now,

We have to find out how many 176 Ω resistors should be connected in parallel to obtained a resultant resistance of 44 Ω.

Let the number of 176 Ω resistors required be x.

then,

$\rm\longrightarrow\:\dfrac{1}{44}=\dfrac{1}{176}\times\:x$

$\rm\longrightarrow\:44x=176$

$\rm\longrightarrow\:x=\cancel\dfrac{176}{44}$

$\rm\longrightarrow\:x=4$

Hence,4 resistors of 176 Ω each should be connected in parallel.