Question

7. Hybridization present in the CH2=CH-CH3 in each carbon.
a) SP, SP, SP
b) SP?, SP, SP'd c) SP2, SP, SP
d) SP, SP, Spa
f. molecule​

Answer 1

Answer:

may be my answer helps you

Explanation:

To determone hybridisation, in case of hydrocarbon compound just count the number of sigma bonds,

2 sigma bonds = sp hybridisation

3 sigma bonds = sp

2

hybridisation etc.

So the correct option is [A]