Question

7-I = 36 - Finda vector perpendicular to A in the plane of Ā ​

Answer 1

Answer

Given, a=3i^+2j^+2k^ 

and b=i^+2j^−2k^.

Now, a+b=(3i^+2j^+2k^)+(i^+2j^−2k^)=4i^+4j^+0k^

a−b=(3i^+2j^+2k^)−(i^+2j^−2k^)=2i^+0j^+4k^

We know that the unit vector perpendicular to both