7. (i) x³ + 6x² + 12x + 16 factorisation
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4
Required Answer:-
Given to factorise:
- x³ + 6x² + 12x + 16
Solution:
Given,
x³ + 6x² + 12x + 16
= x³ + 4x² + 2x² + 8x + 4x + 16
Now, we will group each term,
= x²(x + 4) + 2x(x + 4) + 4(x + 4)
Now, we will take (x + 4) as common
= (x + 4)(x² + 2x + 4)
Now, we will check if x² + 2x + 4 can be factorised or not.
a = 1, b = 2 and c = 4
So, b² - 4ac
= 2² - 4 × 4
= 4 - 16
= -12 which is negative.
So, x² + 2x + 4 cannot be factorised.
Hence, the factorised form is (x + 4)(x² + 2x + 4)
Answer:
- The factorised form is (x + 4)(x² + 2x + 4)
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