Question

7 identical lamps of resistance 220 ohms each are connected to a 220 volt line as shown in the figure then the reading in the ammeter will be

Answer 1

equivalent resistance=220/7
then V=IR
I=V/R
I=220/220/7
I=7A
SO 7A PASSES THROUGH WHOLE CIRCUIT
THEN EACH RESISTANCE SUFFERS 1A OF CURRENT
THEN RESISTANCE THAT ARE AWAY FROM AMMETER ARE 5 FROM WHICH CURRENT GOES TO AMMETER
THEN READING WILL BE 5A
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Answer 2

Answer:

Current flowing through ammeter is 5 Ampere .

Explanation:

• If n resistances of equal value, R are connected in parallel, then the equivalent resistance is given by

$R(eq) = \frac{R}{n} ohms$In the given circuit :

• All the seven lamps having resistances 220 ohm are connected in parallel.
• The ammeter is connected in between point ab and bc.

Solution :

• Two equal valued resistances are connected in parallel between point ab
• Equivalent resistance between points a and b is

$R(ab) = \frac{R}{2} = \frac{220}{2} \\ = 110 \: ohms$

• Five equal valued resistances are connected between point bc
• Equivalent resistance between points b and c is

$R(bc) = \frac{220}{5} \\ = 44 \: ohms$

• From the figure it is clear that, current, I in the ammeter is equal to current flowing in 44 ohms resistance.

$current, I = \frac{V}{R} \\ I = \frac{220}{44} = 5A$

• Hence, current flowing through ammeter is 5 Ampere .