Science, asked by appignanu, 2 months ago

7. Identify the type of reaction(s) in the following equations.
(i)CH4 + 202 ---- → CO2 + 2 H2O
(ii) Pb(NO3)2 + 2K1 - ->Pbl2 + 2KNO3
(iii) CaO + H2O - - > Ca(OH)2 .
(iv) CuSO4 + Zn -> ZnSO4 + Cu​

Answers

Answered by stpatil21
1

Answer:

oxidation reaction

double displacement reaction

combination reaction

displacement reaction

fol low me

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Answered by DivineGirl
3

Answєr :-

  • CH4 + 202 → CO2 + 2 H2O

The combustion of methane or octane is exothermic; it releases energy. CH4 + 2 O2 → CO2 + 2 H2O + energy The energies of the products are lower than the energiies of the reactants.

  • Pb(NO3)2 + 2K1 → Pbl2 + 2KNO3

Pb(NO3)2 – Lead (II) nitrate source:

Other names: Lead nitrate source, Plumbous nitrate source, Lead dinitrate.

Appearance: White colourless crystals, White or colourless crystals.

Names: Potassium iodide, KI Thyrosafe ,Thyroshield ,Iosat ,Kaliumiodid

  • CaO + H2O → Ca(OH)2

This reaction occurs when water is added to dry portland cement to make concrete, and heat evolution of energy as heat is evident because the mixture becomes warm.

  • CuSO4 + Zn → ZnSO4 + CCu

From this reaction we conclude that the copper is reduced from (+2) to (0) oxidation state and zinc is oxidized from (0) to (+2) oxidation state. So, copper is an oxidizing agent and zinc is a reducing agent. Hence, the reducing agent and oxidizing agent are, zinc and copper respectively.

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