Math, asked by Mahira008, 1 month ago

7. If \ -2/3\ ^ 3 is the first factor of (2/3) ^ - 1 then what is another factor of the number.​

Answers

Answered by kikhesheyepthomi
0

Answer:

2746 is the answer it may help u

Answered by Swarup1998
3

Given:

(-\dfrac{2}{3})^{3} is the factor of (\dfrac{2}{3})^{-1}

To find:

Another factor of (\dfrac{2}{3})^{-1}

Step-by-step explanation:

Here we simply perform a division operation using laws of indices,

\quad (\dfrac{2}{3})^{-1}\div (-\dfrac{2}{3})^{3}

=(\dfrac{2}{3})^{-1}\div \{-(\dfrac{2}{3})^{3}\}

=\dfrac{(2/3)^{-1}}{-(2/3)^{3}}

=-\dfrac{2}{3}^{-1}\times (\dfrac{2}{3})^{-3}

  • since \dfrac{1}{a^{n}}=a^{-n}

=-(\dfrac{2}{3})^{-1-3}

=-(\dfrac{2}{3})^{-4}

Answer:

Another factor is -(\dfrac{2}{3})^{-4}

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