Question

7. If 2(a²+b^2) = (a+b)^2, then show that a = b​

Answer 1

Answer:

2(a² + b²) = (a + b)²

=> 2a² +2b² = a² + b² +2ab

=> 2a² -a² +2b² - b² -2ab = 0

=> a² + b² -2ab = 0

=> (a - b)² = 0

=> a - b = 0

=> a = b ..

hence proved..

Step-by-step explanation:

formula used ;

( a ± b) ² = a² + b² ± 2ab.

$..$

Answer 2

Answer:

heya mate ☺

$2(a ^{2} + b ^{2} ) = (a + b) ^{2} \\ = > 2a ^{2} + 2b ^{2} = a ^{2} + 2ab + b ^{2} \\ = > 2a ^{2} - a ^{2} + 2b ^{2} - b ^{2} + 2ab = 0 \\ = > a^{2} - 2ab + b ^{2} = 0 \\ = > (a - b) ^{2} = 0 \\ = > a - b = \sqrt{0} \\ = > a - b = 0 \\ = > a = b$

✌ hope it helps u ✌

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