Question

7. If 2 is one of the root of the equation x^2 + 2x + b = 0, find the value of b?​

Answer 1

-8

Step-by-step explanation:

Given:

2 is Root of Equation,

Solution: Just Put 2 in equation at the place of x, As

$\sf \: {x}^{2} + 2x + b = 0 \\ \\ \sf \: {2}^{2} + 2.2 + b = 0 \\ \\ \sf 4 + 4 + b = 0 \\ \\ \sf b = - 8$

I think answer is -8

Answer 2

Answer:

$\huge\mathcal{\red{Hola!}}$

$\huge\mathfrak{\green{Answer}}$

$\huge\mathcal{\red{-8}}$

Step-by-step explanation:

Given:-

2 is one of the root of the given equation.

To find:-

Value of b in the given equation.

p(x) = x^2 +2x + b = 0

$\huge\mathcal{\red{x=2}}$

putting x = 2, we have

${x}^{2} + 2x \: + b \: = 0 \: \: \\ = > {2}^{2} + 2(2) + b = 0$

$= > 4 + 4 + b = 0$

$8 + b = 0$

$= > b = 0 - 8$

$b = - 8$

$\huge\mathcal{\green{All \ the \ very \ best!}}$

$\huge\mathfrak{\red{@MissTranquil}}$