Question

7. If 6 men and 8 boys can do a piece of
work in 10 days and 26 men and 48
boys can do the same in 2 days, the
time taken by 15 men and 20 boys to
do the same type of work will be
(a) 5 days
(b) 4 days
(c) 6 days
(d) 7 days​

Answer 1

Answer:

4 days

Step-by-step explanation:

Given that

6 men and 8 boys can do a piece of work in 10 days

26 men and 48 boys can do the same in 2 days

As the work done is equal,

10(6M + 8B) = 2(26M + 48B)

60M + 80B = 52M + 96B

=> M = 2B

=> B = M/2 ……(1)

Now Put (1) in 15M + 20B

=> 15M + 10M = 25M

Now, 6M + 8B in 10 days

=> (6M + 4M) 10 = 100M

Then D(25M) = 100M

=> D = 4 days.