Question

7. If 665 mL of a 0.875 M KBr solution are boiled gently to
concentrate the solute to 1 45 M, what will be its final volume?​

Answer 1

Answer:

401.29

Explanation:

WE KNOW THE FORMULA :

M1V1 = M2V2

HENCE

665 × 0.875 = 1.45 × V2

V2 = 665 × 0.875/1.45

V2 = 401.29 ml

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Answer 2

Answer:

The final volume of solute= 401mL

Explanation:

• The total number of moles of the solute in a given solution's molarity is expressed as moles of solute per litre of solution.

• The molarity unit is mol L - 1 .
• Molarity is most commonly used unit of concentration that is respresented by M.
• The ratio employed to indicate the solution's concentration is called its molarity. Understanding a solution's molarity is important since it allows one to determine the actual concentration as well as whether the solution is diluted or concentrated.

$Original: M_{1} = 0.875 M, V_{1} = 665 mL\\\\Final: M_{2} = 1.45 M, V_{2}= ? mL\\\\For concentration: M_{1}V_{1} = M_{2}V_{2}$

M1 = the initial concentration

V1 = the initial volume

M2 = the concentration of solution after mixing

V2= the total final volume.

$Then, \\V_{2} = V_{1} * (M_{1}/M_{2})\\ \\Final volume, V_{2} = 665 * (0.875/1.45) mL \\\\V_{2}= 401 mL$

To learn more about molarity,visit:

https://brainly.in/question/1159016

To learn more about solute,visit:

https://brainly.in/question/526204

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