Question

7. If 80 kg of ration lasts for 15 days, how much ration is required to last for 75 days?

​

Answer 1

Answer:

9000 is my aunswer thak you

Answer 2

Step-by-step explanation:

Let us say that a soldier eats 'n' units of food in a day.

Let us say that a soldier eats 'n' units of food in a day.Total ration available = 100 soldiers * 10 days * n = 1000n

Let us say that a soldier eats 'n' units of food in a day.Total ration available = 100 soldiers * 10 days * n = 1000nIn 2 days, 100 soldiers would consume = 100n*2 = 200n

Let us say that a soldier eats 'n' units of food in a day.Total ration available = 100 soldiers * 10 days * n = 1000nIn 2 days, 100 soldiers would consume = 100n*2 = 200nRemaining food = 1000n - 200n = 800n

Let us say that a soldier eats 'n' units of food in a day.Total ration available = 100 soldiers * 10 days * n = 1000nIn 2 days, 100 soldiers would consume = 100n*2 = 200nRemaining food = 1000n - 200n = 800nNumber of soldiers = 100 + 60 = 160

Let us say that a soldier eats 'n' units of food in a day.Total ration available = 100 soldiers * 10 days * n = 1000nIn 2 days, 100 soldiers would consume = 100n*2 = 200nRemaining food = 1000n - 200n = 800nNumber of soldiers = 100 + 60 = 160Amount of food these soldiers will eat in a day = 160n

Let us say that a soldier eats 'n' units of food in a day.Total ration available = 100 soldiers * 10 days * n = 1000nIn 2 days, 100 soldiers would consume = 100n*2 = 200nRemaining food = 1000n - 200n = 800nNumber of soldiers = 100 + 60 = 160Amount of food these soldiers will eat in a day = 160nNumber of days the food will last = 800n / 160n = 5 days