Question

7. If A = 30°, prove that :
2 tan A
(i) sin 2A =
(1+1
1+tan? A​

Answer 1

Answer:

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Answer 2

Answer:

Sin 2A = 2 tan A /(1+ tan*tan A)

Sin 2(30) = 2 tan (30)/ (1+ tan *tan (30))

Sin 60 = 2 tan (30)/ (1+ tan *tan (30))

Root 3/2 = 2* 1/root 3 /(1+ (root 3/3)2 )

Root3/2 = 2/root 3/ (1 + (root 1)2).

Root 3/2 = 2/root 3 / (1+1). ( root and square cancelled)

Root 3/2 = 2/ root 3 / 2

Sin 60 = cosec 60 / cosec 30

Sin 60 = 2