Math, asked by ratnpriya641, 17 days ago

7. If a + b = 6 and a - b = 2 then what will be the value of 8ab(a^2+b^2)?​

Answers

Answered by hemnagsai
1

Answer:

1280

Step-by-step explanation:

a and b can only be 4 and 2 as it is the only possibility

so now,

             substituting the values,

       =>8*4*2(4^2+2^2)

        =64(16+4)

        =64*20

        =1280

Therefore, the answer is 1280.

Answered by pradeep200117
0

Answer:

The answer of this question is 1280

Step-by-step explanation:

a+b=6

a=6-b - equation 1

a-b=2

from equation 1

6-b-b=2

11280-2b=-4

b=2 - equation 2

from 2

a=6-b

a=6-2

a=4

8ab(a^2+b^2)

8×4×2(4^2+2^2)

64(16+4)

64×20

1280

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