=
7. If a, b are the zeros of the polynomial f(x) = x2 - p (x + 1) - c then
(a + 1) (B + 1) =
(a) 1
(b) 0
(c)-1
(d) 2
Answers
Answered by
1
Step-by-step explanation:
f(x)= x2-p(x+1)-c=0
f(x)= x2-px-(p+c)=0
so alpha+betha=p
alpha× betha=(-p+c))
(alpha+1) (betha+1)=0
alpha×betha+alpha+betha+1=0
-p-c+p+1=0
-c+1=0
c=1 (ans)
so answer is OPTION A.
hope it's helpful to you ☺️
Similar questions