Question

7. If A+B=C and A^2+B^2=C^2, then prove that A and B are perpendicular to each other​

Answer 1

Step-by-step explanation:

Taking Them as vectors,

vector a + vector b = vector c

Which means

C^2 = A^2 + B^2 + 2 A B cosx

Where x is the angle between vector a & vector b

But it is given that

A^2+B^2= C^2

Thus

C^2 = C^2 + 2 A B cosx

2A B cosx = 0

A &B are not zero therefore

Cosx = 0

X = 90 degree

Thanks