Question

7. If 'α' and 'ß' are zeroes of p(x) = 2x²-x-6, then the value of 1/α+1/ß is : *

Answer 1

Answer:

1/-6

Step-by-step explanation:

Alpha + beeta =-b/a

=1/2

Alpha * beeta =c/a

=-6/2=-3

1/α+1/β= β+α/αβ=1/2/-3=1/-6