Question

7. If cot 0 =
7,
8
evaluate : (i)
(1 + sin 0) (1 - sin o)
(1 + cos 0) (1 - cos O)
(ii) cota e​

Answer 1

cot0°=7/8

7,8,√10 are approximately Pythagoras theorem

now sin0°=8/√10,cos0°=7/√10

then 1²-sin²0°=1-8²/(√10)²=1-64/10=-54/10

similarly 1²-cos²0°=1²-7²/(√10)²=1-49/10

=10-49/10=-39/10

ii) I didn't understand that question so sorry for not answering