Question

7. If cot theta=7/8
evaluate
(I) (1 + sin theta) (1 - sin theta)/
(1 + cos theta) (1 - cos theta)
(ii) cot square theta


plz step by step answer.
quick​

Answer 1

Hii its tom85

where @=theta

sin @)(1+sin@)/(1+cos@)(1-cos@)

1-sin^2@/1-cos^2@

cos^2@/sin^2@

cot^2@

now putting the value of cot@

49/64

2)cot^2@=(7/8)^2=49/64

using identity

sin^2@ + cos^2@=1

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hope it may helps you dude