Question

7. If D is the midpoint
of the hypotenuse AC of a right-angled triangle ABC, prove that BD = halfAC​

Answer 1

Answer:

it is proven by the properties of triangle

Answer 2

Step-by-step explanation:

draw line parallel to AB and through D this line intersect BC in point E you can prove easily that DBC is a right triangle

we have by applying pythagore theoreme to ABC and BDE triangles

Ac^2= BC^2+AB^2

and

BD^2 =B^2 + DE^2

so BD^2 = B^2+(C^2- B^2)=C^2 = then BD = DC= 1/2 AC