(7) If for any A.P. d = 5 then t18-t13
(B) 20 (C) 25
(A) 5
(D) 30
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14
Answer:
Let first term = a
Common difference = d = 5
So
t18 - t13
= (a+17d) - (a+12d)
= 6d
= 30
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